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These Vicious Masks (These Vicious Masks, #1) cover

These Vicious Masks (These Vicious Masks, #1)

Spotify — not confirmed On Apple Books

England, 1882. Evelyn is bored with society and its expectations. So when her beloved sister, Rose, mysteriously vanishes, she ignores her parents and travels to London to find her, accompanied by the dashing Mr. Kent.

About These Vicious Masks (These Vicious Masks, #1)

England, 1882. Evelyn is bored with society and its expectations. So when her beloved sister, Rose, mysteriously vanishes, she ignores her parents and travels to London to find her, accompanied by the dashing Mr. Kent. But they're not the only ones looking for Rose. The reclusive young gentleman Sebastian Braddock is also searching for her, claiming that both sisters have special healing powers. Evelyn is convinced that Sebastian must be mad, until she discovers that his strange tales of extraordinary people are true—and that her sister is in graver danger than she feared.

Description via Apple Books · source.

Where to listen & where it's available

These Vicious Masks (These Vicious Masks, #1) is available as an audiobook on Apple Books. We haven't confirmed it on Spotify yet — but you can still search there below.

Spotify Not confirmed on Spotify's audiobook catalog yet.
Apple Books Confirmed audiobook Open on Apple Books ▸

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These Vicious Masks (These Vicious Masks, #1) — frequently asked

Is These Vicious Masks (These Vicious Masks, #1) on Spotify?
We haven't confirmed These Vicious Masks (These Vicious Masks, #1) on Spotify's audiobook catalog yet. Spotify audiobooks are included with Premium (up to a monthly listening limit) in supported markets.
Is These Vicious Masks (These Vicious Masks, #1) on Apple Books?
Yes — These Vicious Masks (These Vicious Masks, #1) is available as an audiobook on Apple Books.
Who wrote These Vicious Masks (These Vicious Masks, #1)?
These Vicious Masks (These Vicious Masks, #1) is by Tarun Shanker.
Where can I buy the These Vicious Masks (These Vicious Masks, #1) audiobook?
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